Franco Mocke

Hello,

I have to collect contact details via a form on my site, and then send it to another website via this format:

tools/postLead.php?mwaid=303&title=Mr&name=Franco&surnam e=Mocke&idnumber=234253453456&cellno=ertertert&tel no=ertert&email=ertret@gmail.com

Obviously my contact form has the fields "Title", "Name" etc...

Now, I used the postback method of the form, and set the action to a .php page where I collect the variables, put the strings together to create the URL as above.

Now after that, how do I send the data? Meaning how do I click on the link without opening a page?

Would appreciate any help, thanks!

Voon

<?php
// process your $_GET or $_POST variables here
header("Location: /tools/postLead.php?" . http_build_query($_GET));
// or $_POST depend on your form method
// note: no echo before header is sent
?>

hope this helps..

=)

Franco Mocke

Thanks Voon, but I'm a bit confused! Here is exactly what I have to do:

<?php

$title=$_POST[title];
$name=$_POST[name];
$surname=$_POST[surname];
$contact=$_POST[contact];
$email=$_POST[email];


$url= "http://www.miway.co.za/tools/postLead.php?mwaid=303&title=" . $title . "&name=" . $name . "&surname=" . $surname . "&idnumber=8808265175081&cellno=" . $contact . "&telno=&email=" . $email;

?>

Now, after that I want to "activate" the $url, in other words I want to open the page without opening it, just sending the data.

Voon

If you want to open the page without opening it, use either fopen or file_get_contents. I would choose file_get_contents as it is easier.

$src = file_get_contents($url);
// echo $src if you want to ...

=)

Franco Mocke

Thanks man that worked great!

Voon

Your welcome..

=)