Need help on CSS link coding...
I am re-coding into this into a single line of code, but it doesn't work...
Here's the original old-type coding:
a.menu:link{ color: #3A88CC; font-size: 10pt; text-decoration: none; font-weight: thinner; font-style: normal; font-family: arial; }
a.menu:link{font: thinner normal 10pt "Arial"; text-decoration: none; color: #3A88CC;}
The single line should work well. First is "style", second is "family"...
The problem is that "Arial" doesn't kick in... it appears Times New Roman (standard).
How do I write the single line command correctly so that it sees "Arial"?
(tried: arial/Arial/"Arial")
-
Istvan Horvath -
Thanks
Signature{{ DiscussionBoard.errors[7480995].message }} -
-
shipwrecked -
Thanks - 1 reply
{{ DiscussionBoard.errors[7482886].message }}-
Brandon Tanner -
Thanks
Signature{{ DiscussionBoard.errors[7483428].message }} -
-
-
shipwrecked -
Thanks - 1 reply
{{ DiscussionBoard.errors[7486897].message }}-
Brandon Tanner -
Thanks - 1 reply
Signature{{ DiscussionBoard.errors[7487840].message }}-
shipwrecked -
Thanks - 1 reply
{{ DiscussionBoard.errors[7491784].message }}-
Brandon Tanner -
Thanks
Signature{{ DiscussionBoard.errors[7493437].message }} -
-
-
-
-
shipwrecked -
Thanks
{{ DiscussionBoard.errors[7519943].message }} -