Hi,

It is really difficult and more over I don't know that,

But you can try this ,

1.Divide the images into even numbers ie, (if you have 30 images, place it in six div's each containing 5 images).

2. Give the id value of each div from one to six(by words) respectively.

3.Now, hide all five div's except first div by using it "style='display:none;'". After that

4.At the end open a div and and place the numbers 1 | 2 | 3| 4 | 5 |6

5. Anchor these numbers to a javascript function like this
<a href="javascript:show('one');">1</a>

similarly to all numbers,

6. Finally, define the show(a) and in it
function show(a) {
document.getElementById('one').style.display = "none";
document.getElementById('two').style.display = "none";
document.getElementById('three').style.display = "none";
document.getElementById('four').style.display = "none";
document.getElementById('five').style.display = "none";
document.getElementById('six').style.display = "none";

document.getElementById(a).style.display = "block";
}

It will do..

Yes, they don't need MySQL, but I guess their solution is even more complicated - basically you have to come up with your own file structure to replicate a database then.


You can always work with a simple text file and read it line by line with a function like file(), then you can use count() to determine how many lines there are. Final step is then to display the images for the current page and show links to the other pages.

A line in this txt file could look like this

appletree.gif|An apple tree|appletree.html

With explode(), you can then easily split the information contained in such a line.

You can then just use an offset and start showing images beginning with the x-th element of the array.

Did that help? What is it exactly that you want to achieve?