lol are you on codeacademy?

This page on php.net might help you.

$c=0;
while ($c<100){
$c=$c+3;
echo "$c<br>";
}

There are lots of ways to write this, but here's one:



WF is stripping out half the code so I took a screenshot and inserted that.

% is the modulus operator and returns the remainder of integer division.

A multiple of 3 will have a remainder of 0 when divided by 3.

A multiple of 5 will have a remainder of 0 when divided by 5.

By checking both those conditions in series, you'll print "Fizz" then "Buzz" when the number is a multiple of both 3 and 5.

for($i = 0 ; $i < $num ; $i++)
{
if($i%3 == 0 && $i%5== 0)
echo "fyzzbyzz";
else if($i%3 == 0)
echo "fyzz";
else if($i%5 == 0)
echo "byzz";
}

Hope the above code will help you understand

Sorry jiffy I should have read the entire message.

Thank you very much You got it right the first time thank you for the code I totaly got it I just haven't been coding for 6 months or so being rusty and tring to get back into it the first code i wrote for this was a pregrep and replace but was having a prob with numbers on it. I was wondering when you a pregrep replace with a number do you need to do something like this '/3/' or is it '{3}' just never had to do a number in a pregrep.

Do you mean preg_replace, which means PCRE (perl-compatible regular expression) regular expression replace? Pregrep isn't a word or nickname for anything.

If you want to match the number 3, the pattern is just 3. No slashes, no curly braces. {3} would tell the regular expression matcher to repeat the previous pattern 3 times. The whole pattern, though, needs to be surrounded by a delimiter, which can be any character you want. The forward slashes are commonly chosen.

Regular expressions are a complex topic all of their own.

If you just want to replace a literal string with a different literal string (i.e. change all the "3"s to something else), you don't need a regular expression. Use str_replace.