So I have a long tail keyword and I would like to measure the difficulty it would take to rank on google in the first 5 positions for it. 1. So how to measure the difficulty ?
How to measure the difficulty of a keyword
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So I have a long tail keyword and I would like to measure the difficulty it would take to rank on google in the first 5 positions for it.
1. So how to measure the difficulty ?
I go through the search results manually, check the first 10 sites manually and see their PRs, onpage seo strengths and then think if my own site is better than them.
I would also do intitle, inanchor tests to see volume of search results.
What else can be done ?
I am considering this keyword for example
##
install apache tomcat on ubuntu
##
There are lots of blog posts, upto 5th page that have a post on this topic, and most being wordpress blogs, they are well optimised.
If my own website has a higher pagerank/backlink count than those appearing on page #1, can I still write a post and make it to the first page ?
Most tutorials say that I just need to outperform the first page competitors and the number of competitors does not matter. Mathematically that sounds correct, but is it equally easy to achieve practically ?
1. So how to measure the difficulty ?
I go through the search results manually, check the first 10 sites manually and see their PRs, onpage seo strengths and then think if my own site is better than them.
I would also do intitle, inanchor tests to see volume of search results.
What else can be done ?
I am considering this keyword for example
##
install apache tomcat on ubuntu
##
There are lots of blog posts, upto 5th page that have a post on this topic, and most being wordpress blogs, they are well optimised.
If my own website has a higher pagerank/backlink count than those appearing on page #1, can I still write a post and make it to the first page ?
Most tutorials say that I just need to outperform the first page competitors and the number of competitors does not matter. Mathematically that sounds correct, but is it equally easy to achieve practically ?
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