# Any Math experts?

27 replies
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HI

Any math experts out there?

I want to find the %of hitting 4 wins of a system that wins 70% of the time? i am afraid my math stopped about 20+ years ago.

Anyone?

Thank you
• Banned
2.8%?

..........................
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Hi
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•  Originally Posted by yukon 2.8%? ..........................
thanks my friend. So fast..may i see the equation for working this out?

I am impressed.
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• I find the question a bit confusing. Doesn't it depend on how many times you've played the system to get the four wins? And isn't the figure of 70% irrelevant?
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•  Originally Posted by alistair I find the question a bit confusing. Doesn't it depend on how many times you've played the system to get the four wins? And isn't the figure of 70% irrelevant?
NO......it's 70%...over how long i have tested this is my business.

If you can't answer it i'd prefer you didn't remark.

Thanks
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• If you hit 4 wins out of 4 plays then it's a 100% hit rate. If you hit 5 wins out of 10 plays then it's a 50% hit rate. But that's all irrelevant if you've already worked out on average it's a 70% hit rate. Unless I'm missing something
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•  Originally Posted by alistair If you hit 4 wins out of 4 plays then it's a 100% hit rate. If you hit 5 wins out of 10 plays then it's a 50% hit rate. But that's all irrelevant if you've already worked out on average it's a 70% hit rate. Unless I'm missing something
Then YOU simply failed to understand the question...

 HI Any math experts out there? I want to find the %of hitting 4 wins of a system that wins 70% of the time? i am afraid my math stopped about 20+ years ago. Anyone? Thank you
If you fixed a coin so it landed on heads 7 out of ten times....what are the chances of getting 4 successive heads on a coin toss? Better?
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•  Originally Posted by trader99 Then YOU simply failed to understand the question... If you fixed a coin so it landed on heads 7 out of ten times....what are the chances of getting 4 successive heads on a coin toss? Better?
Yeah that's better. Ok, I figured out the answer.

Have a nice day.
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• It is 24%

7/10 X 7/10 X 7/10 X 7/10 = 2401/10000 => 24.01/100

ie The Probability of 7/10 (70%) occurring 4 times.

Dan
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•  Originally Posted by jimbo13 It is 24% 7/10 X 7/10 X 7/10 X 7/10 = 2401/10000 => 24.01/100 ie The Probability of 7/10 (70%) occurring 4 times. Dan
so what did Yukon say 3% for?

thx....
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•  Originally Posted by jimbo13 It is 24% 7/10 X 7/10 X 7/10 X 7/10 = 2401/10000 => 24.01/100 ie The Probability of 7/10 (70%) occurring 4 times. Dan
Jimbo,
how do you calculate sequences in the above probabilities?

Say 3 winners and 1 losing..what are the chances of that?

I need to brush up on my math again...

Thx
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•  Originally Posted by trader99 If you can't answer it i'd prefer you didn't remark. Thanks
LOL

Here you can find all your answers.

Math.com - World of Math Online

Have a nice day.
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• Winning is 70% ie 70/100 => 7/10

Losing is 30% ie 30/100 => 3/10

Just multiply.

3 winners and 1 loser is 7/10 x 7/10 x 7/10 x 3/10 = 1029/10000 => 10.29/100 or approx 10%

I got this from GCSE Bitesize on BBC Website

Dan
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•  Originally Posted by jimbo13 It is 24% 7/10 X 7/10 X 7/10 X 7/10 = 2401/10000 => 24.01/100 ie The Probability of 7/10 (70%) occurring 4 times. Dan
Yup. You beat me posting the answer.
And it doesn't matter if it's four in a row. Any random four chances at 70% will give the same answer.

It's a math question, but to get the answer is really a matter of just reasoning it out.

I did it in my head, and rounded the last number.

.7X.7=.49...X.7=.343...X.7 (and this one took a minute)....2401. If the percentage were more than one digit, I wouldn't have been able to do it in my head.
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• Alistair's question was relevant; 4 wins out of 4 attempts is far different than 4 wins out of 40.

Yukon possibly multiplied 0.7 by four, but that's unfortunately not the right approach.

Jimbo13 is correct for the case of four wins out of four: 70%^4 = 24%.

Jimbo13 is on the right path for three wins and a loss, but that's just for one permutation. There are actually four different ways to get three wins and a loss, so you'd multiply his answer by four: 4*(70%^3 * 30%) = 41%.

Since there's an 85% chance that you're going to ask for the other three probabilities: Six ways to get 2W+2L: 6*(70%^2 * 30%^2) = 26%, four ways to get 1W+3L: 4*(70% * 30%^3) = 8%, one way to get 0W+4L: 30%^4 = 1%. Sanity check for all 16 permutations: 24% + 41% + 26% + 8% + 1% = 100%. (Yes, there are decimal places, but I'd bet 50/50 that the original 70% figure isn't likely to be accurate to more than one decimal place in the first place.)

And Trader99 needs to chill when asking for help.
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•  If you can't answer it i'd prefer you didn't remark.
Thank you, mods, for shutting down yet another troll or 12 yr old...whichever....
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• [joke]

A guy stumbles into an internet marketing forum and finds his way into the off topic area and starts asking math questions - expecting to get perfectly correct answers and no other commentary...

[/joke]
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•  Originally Posted by trader99 HI Any math experts out there? I want to find the %of hitting 4 wins of a system that wins 70% of the time? i am afraid my math stopped about 20+ years ago. Anyone? Thank you
4 wins in a row?
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I'm no math expert & I answered a math question at 5:30 AM so you get what you get.

I have no idea how anyone would get 24% for OPs question. That doesn't even look remotely correct, even without a calculator.

Why was OP banned? Is math the new religion?
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•  Originally Posted by yukon I'm no math expert & I answered a math question at 5:30 AM so you get what you get. I have no idea how anyone would get 24% for OPs question. That doesn't even look remotely correct, even without a calculator. Why was OP banned? Is math the new religion?
It's correct. Here's a brief explanation of a similar circumstance:
Finding the probability that some event A happens X times in a row or some other event B happens Y times in a row - Mathematics Stack Exchange
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•  Originally Posted by yukon I have no idea how anyone would get 24% for OPs question. That doesn't even look remotely correct, even without a calculator.
The probability of something happening four times consecutively is the probability of it happening once (70%) to the fourth power. What's wrong with 24%?
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•  Originally Posted by David Beroff The probability of something happening four times consecutively is the probability of it happening once (70%) to the fourth power. What's wrong with 24%?
If he's asking for 4 wins in a row, then it's probably correct. But the way he phrased the questions seems like he may be asking for something else.
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•  Originally Posted by dandagger If he's asking for 4 wins in a row, then it's probably correct. But the way he phrased the questions seems like he may be asking for something else.
The only ambiguity that I saw was in how long he was giving for the four wins to occur. But by not stating this, one is left with a choice of either the minimum period, (i.e., "in a row"), or the maximum, (i.e., "eventually"). Since the probability for the latter is (hopefully) obvious, (i.e., the probability for eventually getting four wins, given enough opportunities, approaches 100%), the only question left to be answered was for the former.
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 Originally Posted by David Beroff The only ambiguity that I saw was in how long he was giving for the four wins to occur. But by not stating this, one is left with a choice of either the minimum period, (i.e., "in a row"), or the maximum, (i.e., "eventually"). Since the probability for the latter is (hopefully) obvious, (i.e., the probability for eventually getting four wins, given enough opportunities, approaches 100%), the only question left to be answered was for the former.
Wow. Well somebody can do math/statistics.

4 in a row is .7*.7*.7*.7=.7^4=.2401

Since the question was poorly asked and has multiple potential answers, I would have to refer to https://en.wikipedia.org/wiki/List_o...atical_symbols and I don't actually care anymore. I'm pretty sure I would have to use images to actually answer the question and yeah screw that.

Also, if this is one of those "smart puzzles" for stupid people and the answer is some kind of trick that I don't know, that crap is absolutely lame and the people behind creating those should have their genitals removed.

"Did you know that 1+1=0?" Dude were speaking english not binary and your insane proof involves an assumption somewhere that is incorrect because the numbers change contexts and anybody who works with numbers in those contexts knows not to mix them together because they have a congruent understanding of what those numbers actually represent.
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•  Originally Posted by irawr Wow. Well somebody can do math/statistics.
Thank you.

 Originally Posted by irawr Also, if this is one of those "smart puzzles" for stupid people and the answer is some kind of trick that I don't know....
I don't think there was any trickery intended here. The OP was a bit curt, and was subsequently (temp?) banned, but I think his original question was perfectly sincere. I don't even think it was posed poorly, and it certainly didn't use any symbols. His later clarification using (biased) coin tosses communicated his original intent pretty clearly.
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•  Originally Posted by yukon Why was OP banned? Is math the new religion?
(video removed due to my paranoia bout getting a kick for posting a video about math and religion) lol
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• Banned
 Originally Posted by yukon Why was OP banned? Is math the new religion?
It's a mathematical probability that if you post in OT and act like an assmonkey, that someone will check out your other posts and notice that you completely hijacked someone else's Joint Venture thread because you didn't want to wait for approval or couldn't get approval for your own.
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